Coin Change2
题目地址:
https://leetcode.com/problems/coin-change-2/description/
题目:
You are given coins of different denominations and a total amount of money. Write a function to compute the number of combinations that make up that amount. You may assume that you have infinite number of each kind of coin.
Note: You can assume that
- 0 <= amount <= 5000
- 1 <= coin <= 5000
- the number of coins is less than 500
- the answer is guaranteed to fit into signed 32-bit integer
Example 1:
Input: amount = 5, coins = [1, 2, 5] Output: 4 Explanation: there are four ways to make up the amount: 5=5 5=2+2+1 5=2+1+1+1 5=1+1+1+1+1
Example 2:
Input: amount = 3, coins = [2] Output: 0 Explanation: the amount of 3 cannot be made up just with coins of 2.
Example 3:
Input: amount = 10, coins = [10] Output: 1
解题思路:
这道题用dp思想可以解。
Link: https://discuss.leetcode.com/topic/79071/knapsack-problem-java-solution-with-thinking-process-o-nm-time-and-o-m-space
Link: https://discuss.leetcode.com/topic/79071/knapsack-problem-java-solution-with-thinking-process-o-nm-time-and-o-m-space
代码:
public int change(int amount, int[] coins) { int[][] dp = new int[coins.length+1][amount+1]; dp[0][0] = 1; for (int i = 1; i <= coins.length; i++) { dp[i][0] = 1; for (int j = 1; j <= amount; j++) { dp[i][j] = dp[i-1][j] + (j >= coins[i-1] ? dp[i][j-coins[i-1]] : 0); } } return dp[coins.length][amount]; }

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